a+b-x/x^2=a^2-b^2/x^3-1/x

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Solution for a+b-x/x^2=a^2-b^2/x^3-1/x equation:


D( x )

x^3 = 0

x = 0

x^2 = 0

x^3 = 0

x^3 = 0

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

a+b-(x/(x^2)) = a^2-((b^2)/(x^3))-(1/x) // - a^2-((b^2)/(x^3))-(1/x)

a-a^2+b+(b^2)/(x^3)-(x/(x^2))+1/x = 0

a-a^2+b+(b^2)/(x^3)-x^-1+1/x = 0

b^2*x^-3 = -(a-a^2+b) // : b^2

x^-3 = -(b^-2*(a-a^2+b))

-3 < 0

1/(x^3) = -(b^-2*(a-a^2+b)) // * x^3

1 = -b^-2*x^3*(-(a-a^2+b)) // : -(b^-2*(a-a^2+b))

1/(-(b^-2*(a-a^2+b))) = x^3

x^3 = 1/(-(b^-2*(a-a^2+b))) // ^ 1/3

x = 1/(b^(-2/3)*(a-a^2+b)^(1/3))

x = 1/(b^(-2/3)*(a-a^2+b)^(1/3))

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